x^2-49x+600=0

Solution for x^2-49x+600=0 equation:

x^2-49x+600=0

a = 1; b = -49; c = +600;
Δ = b2-4ac
Δ = -492-4·1·600
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-49)-1}{2*1}=\frac{48}{2}
=24
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-49)+1}{2*1}=\frac{50}{2}
=25
$